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Find the 40th term of an Ap whose12th term is 47. and the 18th term is 71 |
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Answer» ans: as 12TH term=47 we can WRITE it as a+11d=47-a EQ (where a is FIRST term and d is COMMON difference similarily we can write 18th term as a+17d=71-b eq subtract a eq from b eq we get d=4 a=3 40th term=a+(40-1)d therefore 3+(39)4=3+156=159 hence 40th term is 159 thanku |
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