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find the 2 no. such that their mean proportion is 14 and 3rd proportion=112 |
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Answer» Let the required no. be a and b.Therefore,14 is the mean proportional between a and b.a:14=14:bab= 196. eqn....1and, 112 is third proportional to a and ba:b=b:112b square=112 a. eqn....2From eqn.1;. ab=196. a=196/bsubstituting a =196/b in eqn ...2, we get:b square= 112*196/bb cube=112*196 and, b = 28therefore. a=196/b196/28. = 7therefore the required numbers are 28 and 7 |
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