Heya Kiddo !!==> Let a be the first TERM and d be the common difference Given : a2 = 11 and common difference d = 9==> a2 = a + d by substituting the value of d and a2 in above EQUATION we have, 11 = a + 9 ==> a = 11 - 9==> a = 2 Now, 15th term is given by a15 = a + 14D on substituting both a and d in above equation we get,==> a15 = 2 + 14 X 9 ==> 2 + 126 ==> a15 = 128 Hope it helps you ❤❤❤
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