1.

Find the 10th term from the end of the A.P.8,10,123,......126​

Answer»

>GIVEN:-AP=8,10,12......126

Reverse of the AP 126,124,122 ......10,8

Here a=126,d=a2-a1=124-126=-2,an=8

an=a+(n-1)d

a10=126+(10-1)*(-2)

a10=126+9*(-2)

a10=126-18

a10=108



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