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Find the 10 th term of the HP `(3)/(2), 1, (3)/(4), (3)/(5), ...` |
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Answer» The given HP is `(3)/(2), 1, (3)/(4), (3)/(5),...` The corresponding AP is `(2)/(3), 1, (4)/(3), (5)/(3),...` Here `a = (2)/(3) , d = 1 - (2)/(3) = (1)/(3)` `therefore T_(10)` of the corresponding AP is `a+ (10-1) d = (2)/(3) = (9)(1)/(3) = (11)/(3)` Hence, required term in HP is `(3)/(11)`. |
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