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Find sum of 6 term of gp 0.1,0.01,0.001 |
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Answer» Answer: a = 0.1 R = 0.01/0.1 = 0.1 (r<1) n = 6 SN = a(1 - r^n)/1 - r s6 = 0.1[1 - (0.1)^6]/1 - 0.1 = 0.1[1 - (0.1)^6]/0.9 = [1 - (0.1)^6]/9 = 1/9[1 - (1/10)^6] hope it helps!!!!!! |
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