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Find slope of the line passing through the points \( (-2,6) \) and \( (4,8) \)Find the equation of the line passing through the points \( (-2,6) \) and \( (4,8) \) |
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Answer» (x1,y1) =(-2,6) (x2,y2) =(4,8) slope= (y2-y1)/(x2-x1)= (8-6)/(4+2) 2/6=1/3 equation of the line= y-y1= 1/3(x-x1) or, y-6=1/3(x+2) or. 3y-18=x+2 or, x-3y+20=0 |
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