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Find slope of the line passing through the points \( (-2,6) \) and \( (4,8) \)Find the equation of the line passing through the points \( (-2,6) \) and \( (4,8) \)

Answer» (x1,y1) =(-2,6)   (x2,y2) =(4,8)   

slope= (y2-y1)/(x2-x1)= (8-6)/(4+2) 2/6=1/3

equation of the line=

y-y1= 1/3(x-x1)

or, y-6=1/3(x+2)

or. 3y-18=x+2

or, x-3y+20=0


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