Find slope of tangent of the curve y = ae-xb at the point where it cro – InterviewSolution

1.

Find slope of tangent of the curve y = ae-xb at the point where it crosses the y-axis.

Answer»

The curve cuts y-axis at x = 0

When x = 0, y = ae⁰= a

Now, dy/dx = ae^-xb.(-1/b)

∴ (dy/dx)_(0,a) = ae⁰(-1/b) = -a/b

Hence, required slope of tangent of curve is (-a/b)

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