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Find s10 for an A.P.:1/6,1/4,1/3 |
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Answer» 1/6 , 1/4 , 1/3 ,... are in A.P first term = a = a1 = 1/6 common difference ( d ) = a2 - a1 d = 1/4 - 1/6 d = ( 3 - 2 ) / 12 d = 1/2 S10 = ( 10/2 ) [ 2 × 1/6 + 9 × 1/2 ] = 5 [ 1/3 + 9/2 ] = ( 5/6 ) ( 2 + 27 ) = ( 5 × 29 ) / 6 = 145/6 why you take (3-2)/12 inplace 1/3 1/2 |
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