Find roots of x²+5x+5=0 by quadratic formula

1.	Find roots of x²+5x+5=0 by quadratic formula
Answer» A Quadratic Equation $\sf x^2+5x+<klux>5</klux>=0$ We have to find the roots of given equation By using quadratic formula $\boxed{\sf{x= \dfrac{-<klux>B</klux>\pm\sqrt{b{}^{2}-4ac}}{2a}}}$ Now we have , Coefficient of $\sf x^2$ (a) = 1 Coefficient of x (b) = 5 CONSTANT term (C) = 5 Now find the roots $\sf\bullet a= 1\ \ , \ \bullet \ b= 5 \ \ , \ \bullet\ c= 5$ $\longmapsto\sf x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\ \\ \\ \longmapsto\sf x= \dfrac{-5\pm \sqrt{(5)^2-4\times 1\times 5}}{2\times 1}\\ \\ \\ \longmapsto\sf x= \dfrac{-5 \pm \sqrt{25-20}}{2}\\ \\ \\ \longmapsto\sf x= \dfrac{-5\pm \sqrt{5}}{2}\\ \\ \\ \longmapsto\sf x = \dfrac{-5-\sqrt{5}}{2} \ \ or \ \dfrac{-5+\sqrt{5}}{2}$ So the roots of given equation is $\bigstar{\boxed{\sf{ \dfrac{-5-\sqrt{5}}{2}}}}$ $\bigstar{\boxed{\sf{ \dfrac{-5+\sqrt{5}}{2}}}}$

Answer»

A Quadratic Equation

$\sf x^2+5x+<klux>5</klux>=0$

We have to find the roots of given equation

By using quadratic formula

$\boxed{\sf{x= \dfrac{-<klux>B</klux>\pm\sqrt{b{}^{2}-4ac}}{2a}}}$

Now we have ,

Coefficient of $\sf x^2$ (a) = 1

Coefficient of x (b) = 5

CONSTANT term (C) = 5

Now find the roots

$\sf\bullet a= 1\ \ , \ \bullet \ b= 5 \ \ , \ \bullet\ c= 5$

$\longmapsto\sf x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\ \\ \\ \longmapsto\sf x= \dfrac{-5\pm \sqrt{(5)^2-4\times 1\times 5}}{2\times 1}\\ \\ \\ \longmapsto\sf x= \dfrac{-5 \pm \sqrt{25-20}}{2}\\ \\ \\ \longmapsto\sf x= \dfrac{-5\pm \sqrt{5}}{2}\\ \\ \\ \longmapsto\sf x = \dfrac{-5-\sqrt{5}}{2} \ \ or \ \dfrac{-5+\sqrt{5}}{2}$