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find rhe difference between compound interest and simple intrest of sum rs 12000 at thr rate of 12% p.a for 2 years |
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Answer» Step-by-step explanation: Principal (P) = Rs 12000 Rate of Interest (R) = 12% per annum Time (T) = 2 years To be found :- The difference between Compound Interest (C.I) ans Simple Interest (S.I) Simple Interest (S.I) = \BF \frac{P \times R \times T}{100} Simple Interest (S.I) = \bf \frac{12000 \times 12 \times 2}{100} Simple Interest (S.I) = \bf 2880 ∴ Simple Interest (S.I) = Rs 2880 Now, Compound Interest (C.I) = \bf P[ (1+\frac{R}{100})^T-1] Compound Interest (C.I) = \bf 12000[ (1+\frac{12}{100})^2-1] Compound Interest (C.I) = \bf 12000[ (1+\frac{3}{25})^2-1] as\: \frac{12}{4}=3 \:and\: \frac{100}{4}=25 Compound Interest (C.I) = \bf 12000[(\frac{25+3}{25})^2-1] Compound Interest (C.I) = \bf 12000[(\frac{28}{25})^2-1] Compound Interest (C.I) = \bf 12000[\frac{784}{625}-1] Compound Interest (C.I) = \bf 12000[\frac{784-625}{625}] Compound Interest (C.I) = \bf 12000\times \frac{159}{625} Compound Interest (C.I) = \bf 3052.8 ∴ Compound Interest (C.I) = Rs 3052.8 So, Difference between (C.I) ans (S.I) is = Rs 3052.8 - Rs 2880 = Rs 172.8 |
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