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Find reminder if x raze to power 2017+1 is divisible by x+1

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( {x}^{2017}  + 1) \div( x + 1) \\  \\  \\ \: let \: p(x) =  {x}^{2017}  + 1 \\  \\  \\ by \: the \: remainder \: theorem \:  \\  \\  \\ p( - 1) \: will \: be \: the \: remainder \\  \\  \\ p( - 1) =  {( - 1)}^{2017}  + 1 \\  \\  \\  =  - 1 + 1 \\  \\  \\  = 0 \\  \\  \\ so \: 0 \: is \: the \: remainder \:


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