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Find remainder theorem 3x³+3x²+3x+1/x+2 |
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Answer» Step-by-step explanation: 3x³+2x²-19x+6 when x=2 Since the REMAINDER is 0, x = 2 is an ACTUAL zero. This means that x - 2 is one of the factors. The NUMBERS on the bottom represent the coefficients of the other FACTOR. Notice that the exponents are reduced by 1. 3x³ + 2x² - 19x + 6 = (x - 2)(3x² + 8x - 3) You can factor 3x² + 8x - 3 further. 3x³ + 2x² - 19x + 6 = (x - 2)(3x² + 8x - 3) = (x - 2)(3x - 1)(x + 3) Set each factor to 0 and solve. x - 2 = 0 x = 2 3x - 1 = 0 3x = 1 3x / 3 = 1 / 3 x = 1 / 3 x + 3 = 0 x = -3 ANSWER: {-3, 1 / 3, 2} |
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