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Find radius of a circle having the same area as that of trapezium as shown in the figure.Height of the trapezium is 4 times Pi.​Please give full solution and I will mark u as brainliest if u did

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First we will find out the are of trapezium GIVEN :-

AB = 18

DC = 32

Distance between parallel LINES (H) = 4π

Area of trapezium = \frac{1}{2} × ( SUM of parallel SIDES ) × h

✒ \frac{1}{2} × ( AB + DC ) × h

✒ \frac{1}{2} ×(18+32) × 4π

✒ \frac{1}{2} × 50 × 4π

✒ 25 × 4π

✒ 100π

Now,

✯ Area of circle = Area of trapezium

➙ πr² = 100π

➙ π × r × r = 100 × π

➙ cancelling 'pi' (π) from both sides

➙ r² = 100

➙ r = \sqrt{100}

➙ r = 10

∴ Radius of the circle = 10



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