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Find potential difference between points A and B of the network shown in fig. and distribution of given main current through different resistors. |
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Answer» Between point A and B resistors of `4Omega,6Omega` and `8Omega` resistances are in series and these are in parallel to `9Omega` resistor. ,brgt Equivalent resistance of series combination is `R_(1)=(4+6+8)ohm=18` If equivalent resistance between A and B is `R=(9xx18)/((9+18))ohm=6Omega` Potential difference between A and B is `V=IR=2.7xx6V=16.2V` Current through `9Omega` resistor `=(16.2)/(9)=1.8A` Current through `4Omega,6Omega` and `8Omega` resistors `=2.7-1.8=0.9A` |
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