1.

Find p(1)and p(2) of the polynomial 5y2-3y+7.​

Answer»

Solution :

⏭ Given:

\star \: \boxed{ \tt{ \red{p(y) = 5 {y}^{2} - 3y + 7}}}

⏭ To Find:

  • p(1)
  • p(2)

⏭ Calculation:

  • p(1)

\implies \sf \: p(1) = 5 {(1)}^{2} - 3(1) + 7 \\ \\ \implies \sf \: p(1) = 5 - 3 + 7 \\ \\ \implies \: \boxed{ \tt{ \blue{p(1) = 9}}}

  • p(2)

\implies \sf \: p(2) = 5 {(2)}^{2} - 3(2) + 7 \\ \\ \implies \sf \: p(2) = (5 \times 4) - 6 + 7 \\ \\ \implies \sf \: p(2) = 20 - 6 + 7 \\ \\ \implies \: \boxed{ \tt{ \orange{p(2) = 21}}}


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