1.

Find p(0),p(2) ,p(2) for p(×)=×^3​

Answer»

\bold{\huge{\underline{\underline{\rm{ Given :}}}}}

p(<klux>X</klux>) =  {x}^{3}

\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}

p(<klux>0</klux>) =  ? \\ p(<klux>2</klux>) = ? \:

\huge{\underline{\underline{\purple{♡Solution→}}}}

If x = 0 , then

p(0) =  {0}^{3}

\boxed{\red{p(0) = 0}}

If x = 2 ,

p(2) =  {2}^{3}

p(2) = 2 \times 2 \times 2

\boxed{\red{p(2) = 8}}

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