1.

Find P(0), p (-1) if p(y) = 4 + 3y- y^2 + 5y^2

Answer»

<P>Answer:

4,5

Step-by-step explanation:

GIVEN

p(y)=4+3y-y^2+5y^2

p(0)=4+3(0)-0+0

=4+0

=4

p(-1)=4-3-1+5

=5



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