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Find out the value of x for which the image is formed on the object itself. |
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Answer» Solution :Case I : for first Refraction `n_(2)/v-n_(1)/U=(n_(2)-n_(1))/R` `rArr 1.5/v+1/x=0.5/10` `rArr 1.5/v=0.5/10-1/x` `rArr 1.5/v=(0.5x-10)/(10x)` `rArr v=(15x)/(0.5x-10)` `v=oo` `rArr x=20` CM Case II : `n_(2)=1.5` `n_(1)=1` `R= +10` `u= -x` `v=90` cm `x=30` cm
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