1.

Find out the value of x for which the image is formed on the object itself.

Answer»

Solution :Case I : for first Refraction
`n_(2)/v-n_(1)/U=(n_(2)-n_(1))/R`
`rArr 1.5/v+1/x=0.5/10`
`rArr 1.5/v=0.5/10-1/x`
`rArr 1.5/v=(0.5x-10)/(10x)`
`rArr v=(15x)/(0.5x-10)`
`v=oo`
`rArr x=20` CM

Case II : `n_(2)=1.5`
`n_(1)=1`
`R= +10`
`u= -x`
`v=90` cm
`x=30` cm


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