Find out the sum of 4.075, 2.09, and 0.075 using the correct number of

1.	Find out the sum of 4.075, 2.09, and 0.075 using the correct number of significant digits.A. 6.2 B. 6.24 C. 6.165 D. 6.245
Answer» ☯ AnSwEr : As, we have to find the SUM of 4.075, 2.09 and 0.075, Using significant digits. So, ★ Number of significant digits in 4.075 = 4 ★ Number of significant digits in 2.09 = 3 ★ Number of significant digits in 0.075 = 4 Now, we will calculate their sum. → Sum = 6.24 $\Large{\implies{\boxed{\boxed{\sf{Sum = 6.24}}}}}$ So, OPTION B is correct. $\rule{200}{2}$ ★ Additional Information : ☯ Uncertaininty in measurment When true value is not equal to experimemtal calculations then there os uncertainty in measurment. ↪ For EXAMPLE 2g of $\sf{H_2}$ Molecules = 602,200,000,000,000,000,000,000 But if we write (602,200,000,000,000,000,000,000) as 6.022 × 10²² then our uncertainty in MEASUREMENT can reduce. $\rule{100}{2}$ Now, Mass of H atom. 0.00000000000000000000000166 But if we write (0.00000000000000000000000166) as 6.61 $\times 10^{-25}$ then our uncertainty in measurement can reduce. → Meaningful to present the data, realisitiolly accurating with uncertainity. $\rule{150}{2}$ ★ There are three ways to reduce the uncertainty in measurement. (i) Scientific Notation (ii) Significant figures (iii)Dimensional analysis

Find out the sum of 4.075, 2.09, and 0.075 using the correct number of significant digits.A. 6.2 B. 6.24 C. 6.165 D. 6.245

Answer»

☯ AnSwEr :

As, we have to find the SUM of 4.075, 2.09 and 0.075, Using significant digits.

So,

★ Number of significant digits in 4.075 = 4

★ Number of significant digits in 2.09 = 3

★ Number of significant digits in 0.075 = 4

Now, we will calculate their sum.

→ Sum = 6.24

$\Large{\implies{\boxed{\boxed{\sf{Sum = 6.24}}}}}$

$\rule{200}{2}$

★ Additional Information :

When true value is not equal to experimemtal calculations then there os uncertainty in measurment.

↪ For EXAMPLE 2g of $\sf{H_2}$

Molecules = 602,200,000,000,000,000,000,000

But if we write (602,200,000,000,000,000,000,000) as 6.022 × 10²² then our uncertainty in MEASUREMENT can reduce.

$\rule{100}{2}$

Now, Mass of H atom.

0.00000000000000000000000166

But if we write (0.00000000000000000000000166) as 6.61 $\times 10^{-25}$

then our uncertainty in measurement can reduce.

→ Meaningful to present the data, realisitiolly accurating with uncertainity.

$\rule{150}{2}$

★ There are three ways to reduce the uncertainty in measurement.

(i) Scientific Notation

(ii) Significant figures

(iii)Dimensional analysis