1.

Find out the GMM of the following. Also find out the total number of atoms. a. 20 g Nitrogen (H2) b. 88.75 g Chlorine (Cl2) c. 4 g Calcium (Ca2) , d. 7.75 g phosphorus (p4) (H = 1, Cl =35.5, Ca =40, P=31)

Answer»

a. 20 g of hydrogen (H2): GMM = \(\frac{20}{2}\) = 10 Number of molecules = 10 × 6.022 × 1023

Total number of atoms = 2 × 10 × 6.022 × 1023 

= 20 × 6.022 × 1023

b. 88.75 g of chlorine 

Number of GMM = \(\frac{88.75}{71}\) = 1.25

Number of molecules = 1.25 × 6.022 × 1023

Total number of atoms = 2 × 1.25 × 6.022 × 1023 

= 2.5 × 6.022 × 1023

c. 4 g Calcium (Ca) 

Number of GMM = \(\frac{4}{40}\)\(\frac{1}{10}\) = 0.1 

Number of molecules = 0.1 × 6.022 × 1023

Total number of atoms = 1 × 0.1 × 6.022 × 1023 

= 0.1 × 6.022 × 1023 

d. 7.75 g Phosphorus Number of GMM = \(\frac{7.75}{31}\)\(\frac{1}{4}\) = 0.25 

Number of molecules = 0.25 × 6.022 × 1023



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