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Find out moment of inertia of thick rod of length 'L' radius of crossection 'R' when axis of rotation is at one of the edge of the rod |
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Answer» ml2/3 Explanation: Inertia (I')at axis passing through center of ROD is ml2/12. so ,inertia at l/2 DISTANCE of centre will be; I = I' + m(l/2)2 =ml2/12+ml2/4 =ml2/3. |
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