1.

Find out moment of inertia of thick rod of length 'L' radius of crossection 'R' when axis of rotation is at one of the edge of the rod​

Answer»

ANSWER:

ml2/3

Explanation:

Inertia (I')at axis passing through center of ROD is ml2/12.

so ,inertia at l/2 DISTANCE of centre will be;

I = I' + m(l/2)2

=ml2/12+ml2/4

=ml2/3.



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