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Find maximum height of a projectile using conservation of energy. |
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Answer» ball is launched as a projectile with initial speed V at an angle θ above the horizontal. Using conservation of energy, FIND the maximum height HMAX of the ball's flight. Express your ANSWER in terms of v, g, and θ.I am doing:12mv2v2hmaxhmaxhmax=mghmax+12m(vcosθ)2=2ghmax+(vcosθ)2=(v2−(vcosθ)2)/2g=v2(1−(cosθ)2)/2g=v2sin2θ2g |
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