1.

Find m so that (–2)m + 1 × (–2)3 = (–2)9​

Answer»

(-2)^{m+1} \times (-2)^{3} = (-2)^{9}

\implies (-2)^{(m+1+3)} = (-2)^{9}

\boxed {\pink { a^{m} \times a^{n} = a^{m+n} }}

\implies (-2)^{m+4} = (-2)^{9}

\implies m + 4 = 9

\boxed {\pink { If \: a^{m} = a^{n} \:then \: m = n }}

\implies m = 9 - 4

\implies m = 5

THEREFORE.,

\red { Value \:of \: m } \green { = 5 }

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