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Find KE of the rod having mess 2kg and length 3m which is moving on smooth horizontal surface such that velocity of it's end points are 3m/s and 6m/s as shown. |
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Answer» 18J `omega(r+3)=6` `omega=1` `K=(1)/(2)Iomega^(2)=(1)/(2)((ML^(2))/(12)+md^(2))xxomega^(2)` `& d=r+(l)/(2)` |
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