1.

Find k value if 9xsquare+kx+1=0​

Answer»

Step-by-step explanation:

The given EQUATION if 9x2+kx+1=0

comparing with ax2+bx+c=0

here a=9, b=k , c=1

△ = b2−4ac

= k2−4(9)(1)

= k2−36

The ROOTS are equal so △ MUST be zero

∴ = k2−36=0

= (x+6)(x−6)=0

=x+6=0 or x−6=0

∴ k=−6 or k=6



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