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Find k so that x^3-2x^2+3x+k has (x-1) as a factor |
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Answer» Answer: Assuming a typo in the equation... Should it be 6x^3-kx^2-5x+6 ? DIVIDE (X-3) into this polynomial and you GET 6x^2+(18-k)x+[3(18-k)-5] with remainder of 3[3(18-k)-5]+6 which MUST equal 0 3[3(18-k)-5]+6=0 3[54-3k-5]+6=0 3[49-3k]+6=0 3[49-3k]=-6 49-3k=-2 49+2=3k 51=3k k=51/3=17 or more simply, use Mark M.'s method: F(3) must equal 0 so replace each x with 3 to get the value of k |
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