Find K for which x^4+10x^3+25x^2+15x+K IS EXACTLY DIVISIBLE BY X+7

1.	Find K for which x^4+10x^3+25x^2+15x+K IS EXACTLY DIVISIBLE BY X+7
Answer» ANSWER: k= -91 Step-by-step explanation: p(x) = x⁴+10x³+25x²+15x+k g(x)= x+7 Putting the value of g(x)=0 We get , x+7=0 , x= -7 Now, we have to PUT the value of x in p(x) (-7)⁴+10×(-7)³+25×(-7)²+15×(-7)+k = 0 2401+(-3430)+1225+(-105)+k=0 196-105+k=0 91+k=0 k=-91

Answer»

ANSWER:

k= -91

Step-by-step explanation:

p(x) = x⁴+10x³+25x²+15x+k

g(x)= x+7

Putting the value of g(x)=0

We get , x+7=0 , x= -7

Now, we have to PUT the value of x in p(x)

(-7)⁴+10×(-7)³+25×(-7)²+15×(-7)+k = 0

2401+(-3430)+1225+(-105)+k=0

196-105+k=0

91+k=0

k=-91

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Find K for which x^4+10x^3+25x^2+15x+K IS EXACTLY DIVISIBLE BY X+7

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