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Find k for which f(x) = {(k + x, x = 1), (4x + 3, x ≠ 1) is continuous at x = 1. |
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Answer» lim(x→1) f(x) = f(1) ⇒ lim(x→1) 4x + 3 = k + 1 ⇒ 4 + 3 = k + 1 ⇒ k = 6 |
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