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Find `i` in shown figure. A. 0.2 AB. 0.1 AC. 0.3 AD. 0.4 A |
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Answer» Correct Answer - B `therefore 60 Omega` and `30Omega` resistor are connected in parallel. So, their net resistance `R_(net) = (30 xx 60)/(30+60) = (1800)/90 = 20 Omega` `therefore I = 2/R_(net) = 2/20 = 0.1 A` |
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