Find √i+√-i

1.	Find √i+√-i
Answer» Solve:\xa0{tex} √i+√(-i){/tex}{tex}=√(e^(i π/2) )+√(〖-e〗^(i π/2) ){/tex}{tex}=〖e〗^(i π/4)+ie^(i π/4){/tex}{tex}=〖e〗^(i π/4) (1+i){/tex}{tex}=〖e〗^(i π/4) (√2 e^(i π/4)){/tex}{tex}=√2 e^(i π/2){/tex}{tex}=i√2{/tex}

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