1.

Find: i) \(\frac{7}{11}\) of 330 ii) \(\frac{5}{9}\) of 108 iii) \(\frac{2}{7}\) of 16 iv) \(\frac{1}{7}\) of \(\frac{3}{10}\)

Answer»

i) \(\frac{7}{11}\) of 330 

= \(\frac{7}{11}\) × 330 

= \(\frac{7}{11}\) × 11 × 30 

= 7 × 30 = 210

ii) \(\frac{5}{9}\) of 108 

= \(\frac{5}{9}\) × 108 

= \(\frac{5}{9}\) × 9 × 12 

= 5 × 12 = 60

iii) \(\frac{2}{7}\) of 16 

= \(\frac{2}{7}\) × 16

= \(\frac{2\times16}{7}\) 

= \(\frac{32}{7}\) or \(4\frac{4}{7}\)

iv) \(\frac{1}{7}\) of \(\frac{3}{10}\)

= \(\frac{1}{7}\) × \(\frac{3}{10}\)

= \(\frac{1\times3}{7\times10}\)

= \(\frac{3}{70}\)



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