1.

Find how many three digit natural numbers are divisible by 5

Answer»

100,105........995

a=100
d=105-100=5
an=995

an=a+(n-1)d
995=100+(n-1)5
995-100=(n-1)5
895=(n-1)5
895/5=n-1
179=n-1
n=179+1
n=180

hope this HELPS you


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