1.

Find HCF of the given equation:21py2–56py​

Answer»

ANSWER:

Factorise the FOLLOWING (1 to 8) polynomials: 1. ( i) 8xy3 ... 2. (i) 21 py2 – 56py (ii) 4x3 – 6x2. Solution: (i) 21 py2 – 56py = 7py (3y – 8). (ii) 4x 3 ...



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