1.

Find HCF by using Euclid 's algorithm of 4052 and 12576

Answer»

Using Euclid's algorithm :-

12576 > 4052

4052) 12576 ( 3 12156 ---------- 420) 4052 ( 9 3780 ---------- 272 ) 420( 1 272 ------ 148 ) 272 ( 1 148 ------ 124 ) 148 ( 1 124 ----- 24) 124 ( 5 120 ----- 4 ) 24 (6 24 ---- 0

→ Hence the H.C.F of4052 and 12576 is 4



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