Find four consecutive terms in an A.P. whose sum is 36 and the product

1.	Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2nand the 4th is 105. The terms are in ascending order. answer
Answer» Step-by-step explanation: Let a-2d,a-d,a,a+d,a+2d be the AP a-2d + a-d + a+d + a+2d = 36 => 4A = 36 => a = 9 (a-d)(a+2d) = 105 => (9-d)(9+2d) = 105 => 9(9+2d) - d(9+2d) = 105 => 81 + 18D - 9D - 2d^2 = 105 Solve on ur own from here

Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2nand the 4th is 105. The terms are in ascending order. answer

Answer»

Step-by-step explanation:

Let a-2d,a-d,a,a+d,a+2d be the AP

a-2d + a-d + a+d + a+2d = 36

=> 4A = 36

=> a = 9

(a-d)(a+2d) = 105

=> (9-d)(9+2d) = 105

=> 9(9+2d) - d(9+2d) = 105

=> 81 + 18D - 9D - 2d^2 = 105

Solve on ur own from here

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Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2nand the 4th is 105. The terms are in ascending order. answer​

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Find four consecutive terms in an A.P. whose sum is 36 and the product of the 2nand the 4th is 105. The terms are in ascending order. answer