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find force of attraction between two point charge of magnitude 1microcolumb each placed at a distance of 1 m.also,state the nature of charges. |
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Answer» Use the formula , F= (q1.q2 / 4* pi* epsilon * r^2 ) = (1 * 1C )/(4*pi*8.854.10^-12 * 1) =9 x 10^9 N NATURE OF CHARGES:→When two charges have the same sign their product is positive, which MEANS the force vector is DIRECTED with the separation vector (r̂) and the action is repulsive. →When two charges have the opposite sign their product is NEGATIVE, which means the force vector is directed against the separation vector (r̂) and the action is ATTRACTIVE. |
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