1.

find force of attraction between two point charge of magnitude 1microcolumb each placed at a distance of 1 m.also,state the nature of charges.

Answer»

Use the formula , F= (q1.q2 / 4* pi* epsilon * r^2 )

= (1 * 1C )/(4*pi*8.854.10^-12 * 1)

=9 x 10^9 N

NATURE OF CHARGES:

→When two charges have the same sign

their product is positive,

which MEANS the force vector is DIRECTED with the separation vector (r̂)

and the action is repulsive.

→When two charges have the opposite sign

their product is NEGATIVE,

which means the force vector is directed against the separation vector (r̂)

and the action is ATTRACTIVE.



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