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Find dy/dx, \( y=\sin \left(\log 10^{x}\right) \) |
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Answer» y = sin(log 10x) = sin (x log 10) \(\frac{dy}{dx}\) = cos(x log 10) \(\frac{dy}{dx}\)(x log 10) (By chain rule) = cos (log10x) log 10 = log 10 cos(log10x) |
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