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| 1. |
Find domain and range for f(x)=square root of x-1 |
| Answer» Let f(x) =√x-1 Then, f is defined when x-1>=0= x>=1. So , domain is [1, infinity)For range, let f(x) = yThen , y=√x-1= y^2+1 = xThen x is defined when y is any real no.So, range of f(x) is R (real no.) | |