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Find distance and displacement in the following figure:(plz ans quickly) |
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Answer» the distances are : AB = 20 KM CD = 4 km CB = 8 kmfinding: DB = CB - CD = 8 - 4 = 4 km AC = AB - CD = 20 - 8 = 12 km Displacement associated with direction also along with a magnitude. Let us say that the displacements towards the right side direction are positive. The displacements towards the left are negative. Let the unit VECTOR towards right be denoted by . Displacements:=====================2) distances : AB = 15 km AD = AB - DC - CB = 15 - 5- 8 = 2 km DC = 5 km EB = DB - DE = 5 + 8 - 11 = 2 km CE = CB - EB = 8 - 2 = 6 km displacements :you can write the other displacements from some more points to others, in the same manner. |
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