1.

Find distance and displacement in the following figure:(plz ans quickly)

Answer»

the distances are :       AB = 20 KM            CD = 4 km            CB = 8 kmfinding:   DB = CB - CD =  8 - 4 = 4 km   AC = AB - CD = 20 - 8 = 12 km    Displacement associated with direction also along with a magnitude.  Let us say that the displacements towards the right side direction are positive.  The displacements towards the left are negative.  Let the unit VECTOR towards right be denoted by .   Displacements:=====================2)  distances :  AB = 15 km      AD = AB - DC - CB = 15 - 5- 8 = 2 km     DC = 5 km             EB = DB - DE = 5 + 8 - 11 = 2 km           CE = CB - EB = 8 - 2 = 6 km     displacements :you can write the other displacements from some more  points to others, in the same manner.



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