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Find derivative of tanx^2 using first principle

Answer» f(x+h)=tan(x+h)f\'(x)=limf(x+h)-f(x)/h =limtan (x+h)-tanx/hLim (sin(x+h)/cos(x+h) -sinx/cosx)/hLim sin(x+h)cosx-cos(x+h)sinx/hcos(x+h)cosxLim sin(x+h-x)/hcos(x+h)cosxLim sinh/h 1/cos(x+h)cosx=sec^2x (sin h/h =1)


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