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Find derevative of sinx.cos squarex+secant.x cos Square x |
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Answer» Answer: -SINX ( sinxcosx + 1 ) sinx cos^2x + secx cos^2x => d/dx(sinx cos^2x + secx cos^2x ) => d/dx (sinx cos^2x) + d/dx(secx cos^2x) => -COSX sin^2x - sinx => -sinx( sinx.cosx + 1) |
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