1.

Find area of quadrant of a circle whose radius is 3.5 cm. (use π =22/7)

Answer»

We are GIVEN that radius of the quadrant =3.5cm

∴ AREA of the quadrant AOBCA

=

4

1

πr

2

=

4

1

×

7

22

×(3.5)

2

=9.625cm

2

Area of the triangle AOD

=

2

1

×base×height

=

2

1

×OA×OD

=

2

1

×3.5×2cm

2

=3.5cm

2

HENCE Area of the shaded region =Area of the quadrant-Area of the triangle AOD

=9.625−3.5

=6.125cm

2


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