1.

Find area of a quadrilateral one of whose diagonal is 40 cm and lengths of the perpendiculars drawn from the opposite vertices on the diagonal are 16 cm and one side 12 cm m

Answer»

Solution :

diagonal of a QUADRILATERAL ( d ) = 40cm

lengths of the perpendiculars drawn

from the opposite vertices are H1 and

h2,

h1 = 16 cm ,

h2 = 12 cm

Area ( A ) = [ ( h1 + h2 )d ]/2

=> A = [ ( 16 + 12 )40 ]/2

= ( 30 × 40 )/2

= 30 × 20

= 600 cm²

Therefore ,

Area of the Quadrilateral = A = 600cm²

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