Find all zeroes of the polynomial (2x^2-9x^3 +5x^2+3x-1) if 2 of its z

1.	Find all zeroes of the polynomial (2x^2-9x^3 +5x^2+3x-1) if 2 of its zeroes are (2+ root3) and (2- root3)btw, im giving hundred points.
Answer» Answer: ${\huge{\boxed{\mathcal{\red{An}{\green{sw} {\blue{er}}}}}}}$ It is given that are TWO zeroes the the given expression $2 + \sqrt{3} \: \: \: \: \: and \: \: \: \: 2 - \sqrt{3}$ Therefore $(x - (2 + \sqrt{3} ))(x - (2 - \sqrt{3} )) = (x - 2 - \sqrt{3} )(x - 2 + \sqrt{3} )$ $= {(x - 2)}^{2} - ( { \sqrt{3} }^{2} )$ $= {x}^{2} - 4x + 4 - 3$ $= {x}^{2} - 4x + 1$ THUS , this a factor Now dividing f(x) by x²-4x+1 ●○● The RESULT Of DIVISION is in above ATTACHMENT . ●○● :) $f(x) = ( {x}^{2} + 4x - 1)(2 {x}^{2} - x - 1)$ Hence the other 2 zeroes of f(x) are the zeroes of 2x²-x-1 $\boxed {= 2 {x}^{2} - x - 1 = (2x + 1)(x - 1)}$ Hence other roots are -1/2 and 1 By zero product rule ${\huge{\underline{\overline{\rm{Answer\checkmark}}}}}.[tex]{\huge{\underline{\overline{\rm{Answer\checkmark}}}}}$ ________________ ___________ Hope it helps Mark as BRAINLIEST $\huge\purple{\mathfrak{@phenom}}$