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Find all the two digit numbers,whose digit in the tens place is twice the digit in the units place . |
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Answer» Step-by-step explanation: LET 10y+x be the digit number. It is given that the ten's PLACE is TWICE the digit at unit's place. i.e. y=2x ------(1) Also, (10y+x)+(10x+y)=66 10y+x+10x+y=66 11y+11x=66 ⇒x+y=6 ⇒x+2x=6 [from (1)] ⇒3x=6 ⇒x=2 Form (1), y=2(2)=4 The required number =10(4)+2=42 |
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