1.

Find all natural no. n such that (n+1)^2 is divisible by 7​

Answer»

Step-by-step EXPLANATION:

Let m be the QUOTIENT after DIVIDING (n+1)&^2 by 7

>>(n+1)^2/7=m

>(n+1)^2=7m

(n + 1) =  \sqrt{7m} \\ n =  \sqrt{7m}  + 1 \: where \: m \: is \: a \: real \: number \:  \:



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