Saved Bookmarks
| 1. |
Find all 0's of 2x cube+x square-6x-3 if 2 of it's 0's are -root3,root3. |
|
Answer» There are only TWO ZEROES in this question. Step-by-step explanation: 2x^3+x^2-6x+3 =(2x+1)(x^2-3) ZERO of 2x+1 is 2x+1=0 =>x=-1/2 Zero of x^2-3 is x^2-3=0 =>x=√3 |
|