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Find a vector in the direction of vector 2i - 3j + k6 which has magnitude 21 units. |
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Answer» Required vector = 21((2i - 3j + 6k)/√(4 + 9 + 36)) = 21((2i - 3j + 6k)/√49) = 21((2i - 3j + 6k)/7) = 3(2i - 3j + 6k) = 6i - 9j + 18k |
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