1.

Find (a) the total number and (b) the total mass of protons in 34 mg of NH3 at STP.Will the answer change if the temperature and pressure are changed?

Answer»

(a) 1 mole of NH3 = {1(14) + 3(1)} g of NH3
= 17 g of NH3
= 6.022× 1023 molecules of NH3
Total number of protons present in 1 molecule of NH3
= {1(7) + 3(1)}
= 10
Number of protons in 6.023 × 1023 molecules of NH3
= (6.023 × 1023) (10)
= 6.023 × 1024
⇒ 17 g of NH3 contains (6.023 × 1024) protons. Number of protons in 34 mg of NH3

6.022*1024*34 mg/17000 mg

= 1.2046 × 1022
(b) Mass of one proton = 1.67493 × 10–27 kg
Total mass of protons in 34 mg of NH3
= (1.67493 × 10–27 kg) (1.2046 × 1022)
= 2.0176 × 10–5 kg


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